Concept of motion and it's graphical representation has always been a jargon and a pain to students of class 9th,10th,11th and 12th, be it RBSE or CBSE. Even for cracking IIT and NEET this concept has to be done well. We at Alchemy Learning always insist on getting the concept right.
Distance – Time Graph:
When
an object is moving with uniform velocity, the slope of graph is always a
straight line. In other words, slope of straight line of a distance-time graph
shows that object is moving with uniform speed.
In the
above graph, straight slope line shows that object is moving with uniform
velocity. Slope OA shows the speed of the object.
Calculation of Speed using distance-time graph:
To calculate the SPEED, let
take two points A and B on the slope OB.
Draw a line parallel to
y-axis and another parallel to x-axis from B.
Again draw a line parallel
to y-axis and another parallel to x-axis from point A.
Let, line parallel to
x-axis from point B cut at a point, S2 at y-axis.
Line parallel to x-axis
from point A cut at point, S1 at y-axis.
Let,
line parallel to y-axis from point B cut at t2 at x-axis.
Line parallel to y-axis
from point A cut at t1 at x-axis.
Now, BC= Distance = S2
– S1
and AC
= time = t2 – t1
We know that slope of the
graph is given by the ratio of change in y-axis and change in X-axis.
Or,
where, v= speed,
S2
– S1 = interval of distance and t2
– t1= time interval
Distance – Time Graph of a body moving with Accelerated motion:
When graph of distance Vs
time is plotted for an object moving with accelerated motion, i.e. with
increasing non-uniform speed, the slope of graph will not be a straight line.
The rising trend of slope shows the increasing trend of velocity.
Velocity-Time Graph:
Velocity-time graph of an object moving with uniform velocity:
The slope of a Velocity–time graph of an object moving in
rectilinear motion with uniform velocity is straight line and parallel to
x-axis when velocity is taken along y-axis and time is taken on x- axis
Calculation of distance using
velocity-time graph:
Let two points A and B on
the slope of graph.
Draw two lines parallel to
y-axis AC from point A, and BD from point B.
Let point D at the x-axis
(time axis) is t2 and point C is t1.
Let AB meet at ‘v’ at
y-axis, i.e. object is moving with a velocity, v.
Thus, distance or
displacement by the object is equal to the area of the rectangle (shaded) ABCD.
Thus, Area of ABCD=BD×DC
⇒
s=v(t2 – t1)
Since given object is moving
with constant velocity along a straight line, thus displacement will be equal
to distance covered.
Therefore, Distance or
Displacement = velocity X time interval.
Velocity – Time Graph of an object moving with uniform acceleration
When velocity – time graph
is plotted for an object moving with uniform acceleration, the slope of the
graph is a straight line.
The pattern of slope of the graph shows
that object is moving with uniform acceleration.
Calculation of Displacement and Distance covered by the moving object using velocity time graph:
Let take two points, A and
B at the slope of the graph.
Draw a line from B to BD
and another from point A to AE parallel to y-axis.
Let AD meets at t2 and AEAE at t1 on the time axis.
Thus, Distance covered by
the object in the given time interval (t2–t1) is
given by the area of ABCDE.
Therefore, Distance (s) =
Area of ΔABC + Area of ACDE
⇒S=1/2 (BC X AC)+(AE+ED)
Displacement of the object
during the given time interval (t2−t1) =
Area of ACDE
Thus, Displacement =AE×ED
Velocity time
graph of an object moving with uniform decreasing velocity:
The
slope of the velocity time graph of an object moving with uniform decreasing
velocity with uniform acceleration is a downwards straight line. The straight
downward slope shows the decreasing velocity with uniform acceleration, i.e. retardation.
Velocity time graph of an
object moving with non-uniform velocity:
Equations of Uniformly Accelerated Motion:
There are three
equations of motion for bodies travelling with uniform acceleration. These are
explained below:
1.First Equation of Motion:(Velocity-Time Relation)
v = u +at
Where, v = Final
velocity of body
u = Initial velocity of body
a =
Acceleration
And
t = Time
Using formula for acceleration:
2. Second Equation of Motion:(Position-Time Relation)
3. Third Equation of Motion:
Equations of Motion by Graphical Methods:
Consider
the following velocity time graph:
1. First Equation of Motion:
v = u +at
2. Second Equation of Motion:
Let s be the displacement covered.
As we know that distance covered
by an object is given as area enclosed by the graph,
i.e., Displacement, s = Area of
quadrilateral OABC
3. Third Equation of Motion:
v2 – u2 = 2as
Here, Displacement, s = Area of
trapezium OABC
s = Area of
rectangle ADCO + Area of triangle ABD
NOTE:
ü
Area under the graph speed-time gives distance
travelled.
ü
Slope of the graph speed-time gives
acceleration.
ü
Area under the graph velocity-time gives
displacement.
ü
Slope of the graph velocity-time gives
acceleration.
ü
Slope of the graph distance-time gives speed.
ü
Slope of the graph displacement-time gives
velocity.
ü
Area under the graph acceleration-time gives
change in velocity/speed.
Motion along a circular path:
Motion of an object along a circular
path is called circular motion. Since, on a circular path the direction of the
object is changing continuously to keep it on the path, the motion of the
object is called accelerated motion.
Uniform circular motion:
- When an object moves in a
circular path at a constant speed then motion of the object is called
uniform circular motion.
- In our everyday life, we
came across many examples of circular motion for example cars going round
the circular track and many more. Also earth and other planets revolve
around the sun in a roughly circular orbits.
- If the speed of motion is
constant for a particle moving in a circular motion still the particles
accelerates because of constantly changing direction of the velocity.
- If an object moves in a
circular path with uniform speed, its motion is called uniform circular
motion.
- Here in circular motion, we
use angular velocity in place of velocity we used while studying linear
motion.
- Force which is needed to
make body travel in a circular path is called centripetal force.
We know that the circumference
of a circle of radius r is given by 2πr. If the body
takes t seconds to go once around the circular path of radius r,
the velocity v is given by v=2πr/t
- One thing we must keep in
mind is that uniform linear motion is not accelerated but uniform circular
motion is accelerated motion.
- Motion
of earth around the sun, motion of moon around the earth, motion of a top,
motion of blades of an electric fan, etc. are the examples of circular
motion.
Relative Motion:
The term ‘with respect to’ we used earlier has a significance.
Let’s take an example, you are sitting on your berth inside a compartment of a
moving train. Your distances from the walls, ceiling, floor, windows of
compartment etc. are not changing as time passes. This means that with respect
to the compartment, your position is not changing. So you are at rest with
respect to the compartment. But your distances from a pole on the platform is
changing as time passes. So, you are moving with respect to the platform. This
means that an object can be at rest with respect to one and in motion with
respect to another at the same time. So, the motion is not absolute, rather it
is relative. It is simply how do we perceive the change in position of objects
as time passes.
Now, what do you observe when the train starts moving? You think
that platform is going away. This is true with respect to you and the
compartment. The distance of the platform from you and the compartment is
changing as time passes. So, it looks like the platform is moving as seen from
the compartment. Also, the compartment is moving with respect to the platform.
Suppose two cars A and B are
moving on a highway side by side in the same direction. Both started together
and are moving equally fast. Then the distance between A and B will remain
constant with time and they will perceive the other one as stationary.
Suppose two cars A and B are
moving in opposite direction then the velocity of A as seen by B will be
addition of their velocities (vA+vB) and velocity of B as
seen by A is vA+vB.
Suppose the cars are moving in
same direction but with different velocities vA and vB
respectively. Then the velocity of A as seen by B is vA-vB
and velocity of B as seen by A is vB-vA.
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